Re: Reducing Water Activity in Caviar

From: Ted Labuza (tplabuza@umn.edu)
Date: Fri Aug 24 2007 - 14:57:31 PDT

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    -- 
    Dr. Ted Labuza  
    Morse Alumni Distinguished Teaching Professor of Food Science and
    Engineering
    Department of Food Science and Nutrition Univ. of Minnesota  Rm. 136 A 1354
    Eckles Ave. St Paul 55108
    email - tplabuza@umn.edu ext Msg  6513072985@mobile.mycingular.com  Cell
    651-307-2985
    Office ( 612-624-9701            UM 7  fax 612-625-5272          NFNC 7
    Fax 661-483-3302
    web     http://www.ardilla.umn.edu/Ted_Labuza
    

    From: Ted Labuza <tplabuza@umn.edu> Date: Thu, 23 Aug 2007 09:16:49 -0500 To: SPINALI <spinali@seafoodhaccp.com> Conversation: Reducing Water Activity in Caviar Subject: Re: Reducing Water Activity in Caviar

    Maltodextrin would have little effect. Water activity lowering in solution is based on Raoult's law where

    aw (a is small case and w is subscript) = moles of water/(mole water + moles solute)

    For 1000 g water (155.53 moles) adding in 500 g or maltodextrin

    Maltodextrins have a log normal distribution of molecular weight. Using the average which is ~ 100,000 500 g = 0.005 moles

    aw = (55.53/55.535)=0.999

    Essentially no effect Your best bet would be things like glycerol or maltitol but they will impart undesirable flavor To achieve 0.97 you need to substitute in the above equation for aw (0.97)

    The answer is 1.71 moles per Kg of water

    So if in 100 g of caviar you have 70 g water you need to add 0.07 kg water x 1.7 mole/kg water = 0.12 moles of solute

    For a 200 MW substance then you are adding 200 x 0.12 = 24 g of solute per 70 g water or a 25.5 % (w/weight total) solution. This would probably be unacceptable

    Salt as NaCl (MW = 858.4) is more effective due to lower MW and the dissociation into 2 moles of solute ie Na+ and Cl- so for 70 g water you have aw=0.97=(70/18.01)/((70/18.01)+2 n)) = 3.89/(3.89+2n)

    So n = 0.058 moles = 3.42 g salt which is 3.42/(73.42) = 4.5 % salt solution, yes very salty but inhibitory to many spoilage organisms but would allow growth of Staph, botulinum and some Listeria species ie it is still a PHF.

    -- Dr. Ted Labuza Morse Alumni Distinguished Teaching Professor of Food Science and Engineering Department of Food Science and Nutrition Univ. of Minnesota Rm. 136 A 1354 Eckles Ave. St Paul 55108 email - tplabuza@umn.edu ext Msg 6513072985@mobile.mycingular.com Cell 651-307-2985 Office ( 612-624-9701 UM 7 fax 612-625-5272 NFNC 7 Fax 661-483-3302 web http://www.ardilla.umn.edu/Ted_Labuza

    From: SPINALI <spinali@seafoodhaccp.com> Date: Wed, 22 Aug 2007 21:30:35 -0400 To: <owner-seafood@ucdavis.edu>, <seafood@ucdavis.edu>, <spinali@seafoodhaccp.com> Conversation: Reducing Water Activity in Caviar Subject: Reducing Water Activity in Caviar

    Dear All:

    Hope this is the right address to post a message/question. We are looking for an inexpensive but effective way to reduce the water activity in spoonbill roe to an acceptable level for caviar that will be kept under refrigeration. I believe the water activity should be 0.97 or less. Salting the product to acceptable levels creates an unpalatable product. Will maltodextrin work? Any suggestions?

    All advice would be appreciated.

    Thank you, -- BILL SPINALI FDA Consulting Services, LLC Tel: 978-283-1195 eFax: 801-684-7155 Cell: 617-308-7611


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