Re: Amount of Ice to Chill Fish

From: Ted Labuza (tplabuza@tc.umn.edu)
Date: Sun Jul 16 2000 - 08:11:15 PDT

  • Next message: Andrew Strak: "Re: Amount of Ice to Chill Fish"

    Dr Perlata has a good idea (below) I will take it one more step

    We can create a ice to fish ratio

     mi/mf = (t1 - 0)/Lf = Tf/80

    This says the Kg ice needed per Kg fish (or Lb per lb for that mater) is simply
    80 divided by the fish temperature Thus

    for cold water where Tf = 5 the ratio is 5/80 = 0.06

    for moderate water temp Tf = 20 the ratio is ~ 0.25

    for warm water eg in the Phillipines Tf = 35 ratio is ~ 0.44

    using a cp of one also gives a 20% overcompensation which is in the right
    direction.

    The problem of couse is with a low ratio one may not get the ice throughly mixed
    with the fish

    +++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++

    Responding to the message of <3971922A.9218B6BA@iloilo.net>
    from jperalta@iloilo.net:
    >
    > Dear all:
    >
    > Here is an alternative.
    >
    > And may I use SI units?
    >
    > Assuming no heat losses, and ice temp is 0 C (normal ice temp); and that
    > the final temp of fish sought is not lower than 0 C.
    >
    > Heat given off by the fish = Heat absorbed by melting ice
    >
    > mf cp (t1 - 0) = mi Lf
    >
    > where
    > mf is the mass of fish in kg;
    >
    > cp is the specific heat of fish; I agree with parameters stated earlier
    > but we could simplify further and make it 1(unity); kcal/kg-C
    >
    > t1 is the initial temp of the fish; C
    >
    > Lf is the latent heat of fusion of water; 80 kcal/kg; lastly
    >
    > m1 is the amount of ice; kg, (which is the one sought for), and could
    > easily be calculated.
    >
    > This calculation is a fast estimate of the base ice requirements.. We
    > normally use more than this value to compensate for transport heat
    > losses and other losses/factors.
    >
    > ----------
    >
    > Another alternative is to use a "rule of thumb"; the ratio of 1 part
    > ice to 2 parts fish. This seems to also satisfy the aforementioned
    > calculations, and also compensating for the other heat lossess.
    >
    > Then of course, this assumes that the initial fish temp to be at normal
    > water temp.; which is around 25 C.
    >
    > I hope this helps.
    >
    >
    > Best regards,
    >
    > Jose
    >
    >
    >
    > --
    > -----------------------
    > Jose P. Peralta, Ph. D.
    > Professor/Food Engineer
    > Inst. of Fish Processing Technology
    > College of Fisheries, Univ of the Phil Visayas
    > 5023 Miag-ao, Iloilo, Philippines
    > Tel (63 33) 315 8289
    > FX (63 33) 315 8289, 315 8353
    > Cell (0917) 302 1282
    > EMail jperalta@loilo.net
    > ------------------------
    >
    >
    > .

    Dr Ted Labuza tplabuza@tc.umn.edu
    Prof. of Food Science Dept. of Food Science & Nutrition 136 ABLMS U of Minn St
    Paul, MN 55108 Voice 612-624-9701 Fax 612-625-5272 home fax 651-483-3302
    cellemail 6126697885@mobile.att.net
    http://fscn.che.umn.edu/Ted_Labuza/tpl.html
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